What is the derivative of cot(x+csc(x)) ?

The derivative of cot(x+csc(x)) is -csc^2(x)-cot(x)csc(x)

What is the first derivative of cot(x+csc(x)) ?

The first derivative of cot(x+csc(x)) is -csc^2(x)-cot(x)csc(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (cot (x) + csc (x))

- csc^{2} (x) - cot (x) csc (x)

Solution steps

\frac{d}{d x} (cot (x) + csc (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cot (x)) + \frac{d}{d x} (csc (x))

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

= - csc^{2} (x) - cot (x) csc (x)

x \to 1 lim (\frac{1 - x ^{2}}{ln ( x )})

y^{^{'}} + \frac{4 y}{x} = - \frac{3}{x}

\frac{d}{d x} (2 e^{- 1.5 x} cos (3 x))

\int \frac{2 x}{1 + x ^{2}} d x

(2, 5), (8, 12)

What is the derivative of cot(x+csc(x)) ?
The derivative of cot(x+csc(x)) is -csc^2(x)-cot(x)csc(x)
What is the first derivative of cot(x+csc(x)) ?
The first derivative of cot(x+csc(x)) is -csc^2(x)-cot(x)csc(x)