What is the limit as x approaches 1 of ln(7x)+e^x ?

The limit as x approaches 1 of ln(7x)+e^x is ln(7)+e

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limit as x approaches 1 of ln(7x)+e^x

x \to 1 lim (ln (7 x) + e^{x})

ln (7) + e

Decimal Notation

4.66419 \dots

Solution steps

x \to 1 lim (ln (7 x) + e^{x})

Plug in the value

x = 1

= ln (7 \cdot 1) + e^{1}

Simplify

= ln (7) + e

f (x) = 20 x

y = \frac{x ^{2}}{e ^{x}}

\int \frac{5 x - 2}{x ^{2} - 4} d x

\frac{d}{d x} (sin (8 x + 4))

What is the limit as x approaches 1 of ln(7x)+e^x ?
The limit as x approaches 1 of ln(7x)+e^x is ln(7)+e