What is the derivative of sin(8x+4) ?

The derivative of sin(8x+4) is cos(8x+4)*8

What is the first derivative of sin(8x+4) ?

The first derivative of sin(8x+4) is cos(8x+4)*8

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\frac{d}{d x} (sin (8 x + 4))

cos (8 x + 4) \cdot 8

Solution steps

\frac{d}{d x} (sin (8 x + 4))

Apply the chain rule:

cos (8 x + 4) \frac{d}{d x} (8 x + 4)

= cos (8 x + 4) \frac{d}{d x} (8 x + 4)

\frac{d}{d x} (8 x + 4) = 8

= cos (8 x + 4) \cdot 8

\frac{d}{d x} ((f (x) (4 x))^{2} + 2)

\frac{d}{d x} (cos (a t))

\frac{9}{x ^{2}}

- 0.025 x^{2} + 8 x

y^{^{'}} = x y^{2} + 2 y^{2}, y (0) = 1

What is the derivative of sin(8x+4) ?
The derivative of sin(8x+4) is cos(8x+4)*8
What is the first derivative of sin(8x+4) ?
The first derivative of sin(8x+4) is cos(8x+4)*8