What is the derivative of 9/(x^2) ?

The derivative of 9/(x^2) is -(18)/(x^3)

What is the first derivative of 9/(x^2) ?

The first derivative of 9/(x^2) is -(18)/(x^3)

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derivative of

\frac{9}{x ^{2}}

- \frac{18}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{9}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 2 x^{- 2 - 1})

Simplify

9 (- 2 x^{- 2 - 1}) : - \frac{18}{x ^{3}}

= - \frac{18}{x ^{3}}

- 0.025 x^{2} + 8 x

y^{^{'}} = x y^{2} + 2 y^{2}, y (0) = 1

f (x) = \frac{2 x ^{2} - 6 x + 5}{2 ( 2 x - 3 )}

\frac{d y}{d x} = 4 x e^{3 y}

x y^{^{'}} + 2 y = 4 cos (x)

What is the derivative of 9/(x^2) ?
The derivative of 9/(x^2) is -(18)/(x^3)
What is the first derivative of 9/(x^2) ?
The first derivative of 9/(x^2) is -(18)/(x^3)