What is the solution for yln(x)-x^2y=xy^' ?

The solution for yln(x)-x^2y=xy^' is y=e^{c_{1}+(-x^2+ln^2(x))/2}

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yln(x)-x^2y=xy^'

y ln (x) - x^{2} y = x y^{^{'}}

y = e^{c_{1} + \frac{- x ^{2} + l n ^{2} ( x )}{2}}

Solution steps

y ln (x) - x^{2} y = x y^{'} (x)

Solve separable ODE:

y = e^{c_{1} + \frac{- x ^{2} + l n ^{2} ( x )}{2}}

y = e^{c_{1} + \frac{- x ^{2} + l n ^{2} ( x )}{2}}

\frac{\partial}{\partial y} (x^{3 y})

x \to 0 lim (a^{\frac{1}{x}})

\int x e^{(x + 2)} d x

y^{^{''}} + 7 y^{^{'}} + 10 y = 0

\int - sinh (x) d x

What is the solution for yln(x)-x^2y=xy^' ?
The solution for yln(x)-x^2y=xy^' is y=e^{c_{1}+(-x^2+ln^2(x))/2}