What is the limit as x approaches 3 of x+a+b ?

The limit as x approaches 3 of x+a+b is 3+a+b

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limit as x approaches 3 of x+a+b

x \to 3 lim (x + a + b)

3 + a + b

Solution steps

x \to 3 lim (x + a + b)

Plug in the value

x = 3

= 3 + a + b

\int s 6^{s} d s

\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1}

\frac{d}{d x} (e^{x - 6})

y = (2 x^{3} + 1)^{2}

y^{^{'}} + 4 y = 3 x^{2} e^{- 4 x}

What is the limit as x approaches 3 of x+a+b ?
The limit as x approaches 3 of x+a+b is 3+a+b