What is the integral from 0 to 1 of (10+xsqrt(x)) ?

The integral from 0 to 1 of (10+xsqrt(x)) is 52/5

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integral from 0 to 1 of (10+xsqrt(x))

\int_{0}^{1} (10 + x x) d x

\frac{52}{5}

Decimal

10.4

Solution steps

\int_{0}^{1} 10 + x x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 10 d x + \int_{0}^{1} x x d x

\int_{0}^{1} 10 d x = 10

\int_{0}^{1} x x d x = \frac{2}{5}

= 10 + \frac{2}{5}

Simplify

10 + \frac{2}{5} : \frac{52}{5}

= \frac{52}{5}

\frac{4 s e ^{- 4 s}}{3 s ^{2} + 27}

\int [x ln (x^{2} + 1)] d x

y^{^{''}} + y = sin (t), y (0) = 0, y^{^{'}} (0) = 0

x y y^{^{'}} = x^{2} e^{\frac{y}{x}} + y^{2}

\frac{d}{d x} (a^{2} x)

What is the integral from 0 to 1 of (10+xsqrt(x)) ?
The integral from 0 to 1 of (10+xsqrt(x)) is 52/5