What is the first derivative of a^2x ?

The first derivative of a^2x is a^2

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derivative of a^2x

\frac{d}{d x} (a^{2} x)

a^{2}

Solution steps

\frac{d}{d x} (a^{2} x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a^{2} \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= a^{2} \cdot 1

Simplify

= a^{2}

(x + 3) (\frac{d y}{d x}) + y = ln (x)

\frac{d ^{2}}{d x ^{2}} ((9 x^{2} + 6)^{6})

\int sin^{4} (\frac{x}{4}) cos (\frac{x}{4}) d x

\frac{\partial}{\partial y} (\frac{2 x}{y})

\frac{d y}{d x} - \frac{( 2 y )}{( 3 x )} + \frac{( x ^{2} + 2 )}{3} \cdot y^{4} = 0