What is the solution for x^{''}+3x=0 ?

The solution for x^{''}+3x=0 is x=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)

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x^{''}+3x=0

x^{^{''}} + 3 x = 0

x = c_{1} cos (3 t) + c_{2} sin (3 t)

Solution steps

x^{''} (t) + 3 x = 0

Solve linear ODE:

x = c_{1} cos (3 t) + c_{2} sin (3 t)

x = c_{1} cos (3 t) + c_{2} sin (3 t)

\frac{\partial}{\partial x} (x^{2} e^{- y})

\int 2 cos (x) - \frac{3}{1 - x ^{2}} d x

f (x) = 2 x^{2}, at x = 3

x \to 3 + lim (\frac{x + 3}{x ^{2} - 9})

\frac{d}{d x} (x^{4} + 5 x y^{3})

What is the solution for x^{''}+3x=0 ?
The solution for x^{''}+3x=0 is x=c_{1}cos(sqrt(3)t)+c_{2}sin(sqrt(3)t)