What is the limit as x approaches 3+of (x+3)/(x^2-9) ?

The limit as x approaches 3+of (x+3)/(x^2-9) is infinity

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limit as x approaches 3+of (x+3)/(x^2-9)

x \to 3 + lim (\frac{x + 3}{x ^{2} - 9})

\infty

Solution steps

x \to 3 + lim (\frac{x + 3}{x ^{2} - 9})

Simplify

\frac{x + 3}{x ^{2} - 9} : \frac{1}{x - 3}

= x \to 3 + lim (\frac{1}{x - 3})

For

x

approaching

3

from the right

, x > 3 \Rightarrow x - 3 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d}{d x} (x^{4} + 5 x y^{3})

\int \frac{2}{t} d t

g (x) = \frac{x ^{2} - 4}{x - 2}

x (x - 3)

\int_{0}^{\frac{5}{2}} 25 - x^{2} d x

What is the limit as x approaches 3+of (x+3)/(x^2-9) ?
The limit as x approaches 3+of (x+3)/(x^2-9) is infinity