What is the derivative of g(x)=(x^2-4)/(x-2) ?

The derivative of g(x)=(x^2-4)/(x-2) is 1

What is the first derivative of g(x)=(x^2-4)/(x-2) ?

The first derivative of g(x)=(x^2-4)/(x-2) is 1

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derivative of

g (x) = \frac{x ^{2} - 4}{x - 2}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4}{x - 2})

Simplify

\frac{x ^{2} - 4}{x - 2} : x + 2

= \frac{d}{d x} (x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 1 + 0

Simplify

= 1

x (x - 3)

\int_{0}^{\frac{5}{2}} 25 - x^{2} d x

\int (9 - x) d x

\frac{d y}{d x} = (\frac{2 y + 5}{6 x + 7})^{2}

\frac{d}{d x} (1 - cos (4 x))

What is the derivative of g(x)=(x^2-4)/(x-2) ?
The derivative of g(x)=(x^2-4)/(x-2) is 1
What is the first derivative of g(x)=(x^2-4)/(x-2) ?
The first derivative of g(x)=(x^2-4)/(x-2) is 1