What is the integral from 1 to 4 of 4/(x^2) ?

The integral from 1 to 4 of 4/(x^2) is 3

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integral from 1 to 4 of 4/(x^2)

\int_{1}^{4} \frac{4}{x ^{2}} d x

3

Solution steps

\int_{1}^{4} \frac{4}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{4}

= 4 [- \frac{1}{x}]_{1}^{4}

Compute the boundaries:

\frac{3}{4}

= 4 \cdot \frac{3}{4}

Simplify

= 3

x \to 0 + lim (x^{\frac{2}{x}})

h \to 1 lim (4 h^{2})

x^{4} - 18 x^{2} + 81

n = 1 \sum \infty \frac{n}{2 n + 3}

y = 2 x^{3}, (- 2, - 16)

What is the integral from 1 to 4 of 4/(x^2) ?
The integral from 1 to 4 of 4/(x^2) is 3