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Popular >

area x,5x-x^2,0,4

Solution

area

x, 5 x - x^{2}, 0, 4

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x - (5 x - x^{2}) d x

Solve

\int_{0}^{4} x - (5 x - x^{2}) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

integral from-1 to 1 of y^2-1-(1-y^2)

\int_{- 1}^{1} y^{2} - 1 - (1 - y^{2}) d y

y^'=-2xy^3,y(-3)=4

y^{^{'}} = - 2 x y^{3}, y (- 3) = 4

limit as x approaches-6-of ((x+3))/(x+6)

x \to - 6 - lim (\frac{( x + 3 )}{x + 6})

integral of (1-x)/(x^2-4)

\int \frac{1 - x}{x ^{2} - 4} d x

tangent of f(x)=x^2-4/x-10,\at x=8 tangent of

f (x) = x^{2} - \frac{4}{x} - 10, at x = 8

Frequently Asked Questions (FAQ)

What is area x,5x-x^2,0,4 ?
The answer to area x,5x-x^2,0,4 is 32/3