What is the integral of 7/(\sqrt[4]{x^3)} ?

The integral of 7/(\sqrt[4]{x^3)} is 28\sqrt[4]{x}+C

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integral of 7/(\sqrt[4]{x^3)}

\int \frac{7}{4 x ^{3}} d x

28 4 x + C

Solution steps

\int \frac{7}{4 x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{4 x ^{3}} d x

4 x^{3} = x^{\frac{3}{4}},

assuming

x \geq 0

= 7 \cdot \int \frac{1}{x ^{\frac{3}{4}}} d x

Apply the Power Rule

: 4 x^{\frac{1}{4}}

= 7 \cdot 4 x^{\frac{1}{4}}

Simplify

7 \cdot 4 x^{\frac{1}{4}} : 28 4 x

= 28 4 x

Add a constant to the solution

= 28 4 x + C

t y^{^{'}} - y = \frac{- t ^{3}}{y ^{2}}, y (1) = 2

\int_{0}^{3} (3 t - 5) d t

n = 1 \sum \infty n^{2} e^{n^{3}}

(\frac{x + 2}{x - 2})^{2}

\int_{1}^{2} \frac{1}{x ^{4}} d x

What is the integral of 7/(\sqrt[4]{x^3)} ?
The integral of 7/(\sqrt[4]{x^3)} is 28\sqrt[4]{x}+C