What is the derivative of 4/(x-3) ?

The derivative of 4/(x-3) is -4/((x-3)^2)

What is the first derivative of 4/(x-3) ?

The first derivative of 4/(x-3) is -4/((x-3)^2)

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derivative of

\frac{4}{x - 3}

- \frac{4}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x - 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x - 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x - 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

= - \frac{1}{( x - 3 ) ^{2}} \frac{d}{d x} (x - 3)

\frac{d}{d x} (x - 3) = 1

= 4 (- \frac{1}{( x - 3 ) ^{2}} \cdot 1)

Simplify

4 (- \frac{1}{( x - 3 ) ^{2}} \cdot 1) : - \frac{4}{( x - 3 ) ^{2}}

= - \frac{4}{( x - 3 ) ^{2}}

\frac{d ^{2}}{d x ^{2}} (3^{x^{2} - x + 5})

17 y^{^{'}} = y

\int \frac{1}{x 4 x ^{2} + 16} d x

x \to 1 lim (e^{7 x^{3} - 7 x})

x \to 5 lim (29 - x^{2})

What is the derivative of 4/(x-3) ?
The derivative of 4/(x-3) is -4/((x-3)^2)
What is the first derivative of 4/(x-3) ?
The first derivative of 4/(x-3) is -4/((x-3)^2)