What is the sum from n=0 to infinity of 1/(n-1) ?

The sum from n=0 to infinity of 1/(n-1) is diverges

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sum from n=0 to infinity of 1/(n-1)

n = 0 \sum \infty \frac{1}{n - 1}

diverges

Solution steps

n = 2 \sum \infty \frac{1}{n - 1}

Apply Series Comparison Test:

diverges

= diverges

f (x) = (e^{- x} - e^{5}) (e^{x} + e^{- 3})

n = j \sum \infty (\frac{3}{4})^{n}

\frac{1}{( s ^{2} + 16 )}

\int_{1}^{2} e^{- x^{2}} d x

\frac{\partial}{\partial y} (x z cos (y))

What is the sum from n=0 to infinity of 1/(n-1) ?
The sum from n=0 to infinity of 1/(n-1) is diverges