What is the integral from 1 to 2 of e^{-x^2} ?

The integral from 1 to 2 of e^{-x^2} is 0.13525…

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integral from 1 to 2 of e^{-x^2}

\int_{1}^{2} e^{- x^{2}} d x

0.13525 \dots

Solution steps

\int_{1}^{2} e^{- x^{2}} d x

Use the nonelementary integral:

\int e^{- x^{2}} d x = \frac{π}{2} erf (x)

= [\frac{π}{2} erf (x)]_{1}^{2}

Compute the boundaries:

0.13525 \dots

= 0.13525 \dots

\frac{\partial}{\partial y} (x z cos (y))

y = x^{3} - 6 x^{2} + 9 x, y = x, x = 0, x = 2

\int \frac{4 e ^{x}}{e ^{x} + π} d x

\frac{d}{d x} (x^{2} sin (x) + x)

f (x) = \frac{2}{x + 1}

What is the integral from 1 to 2 of e^{-x^2} ?
The integral from 1 to 2 of e^{-x^2} is 0.13525…