What is the derivative of (-x+pi/2 tan(x)) ?

The derivative of (-x+pi/2 tan(x)) is -tan(x)+sec^2(x)(-x+pi/2)

What is the first derivative of (-x+pi/2 tan(x)) ?

The first derivative of (-x+pi/2 tan(x)) is -tan(x)+sec^2(x)(-x+pi/2)

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\frac{d}{d x} ((- x + \frac{π}{2}) tan (x))

- tan (x) + sec^{2} (x) (- x + \frac{π}{2})

Solution steps

\frac{d}{d x} ((- x + \frac{π}{2}) tan (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = - x + \frac{π}{2}, g = tan (x)

= \frac{d}{d x} (- x + \frac{π}{2}) tan (x) + \frac{d}{d x} (tan (x)) (- x + \frac{π}{2})

\frac{d}{d x} (- x + \frac{π}{2}) = - 1

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= (- 1) tan (x) + sec^{2} (x) (- x + \frac{π}{2})

Simplify

= - tan (x) + sec^{2} (x) (- x + \frac{π}{2})

\frac{\partial}{\partial y} (x z t^{2} y + 1)

f (x) = 9 - 2 x^{2}

f (x) = 6 x e^{x}, at x = 0

\int x (9 - x)^{2} d x

\int \frac{1}{2 x + 2 x} d x

What is the derivative of (-x+pi/2 tan(x)) ?
The derivative of (-x+pi/2 tan(x)) is -tan(x)+sec^2(x)(-x+pi/2)
What is the first derivative of (-x+pi/2 tan(x)) ?
The first derivative of (-x+pi/2 tan(x)) is -tan(x)+sec^2(x)(-x+pi/2)