What is area y=2sin(x),0<= x<= pi ?

The answer to area y=2sin(x),0<= x<= pi is 4

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area y=2sin(x),0<= x<= pi

area

y = 2 sin (x), 0 \leq x \leq π

4

Solution steps

Apply the area formula:

\int_{0}^{π} 2 ∣ sin (x) ∣ d x

Solve

\int_{0}^{π} 2 ∣ sin (x) ∣ d x : 4

The area is:

= 4

x \to \infty lim (x^{2} + 8)

\frac{1}{x}, x^{2}, \frac{1}{2}, 2

\frac{d y}{d x} = (y - 1)^{2} cos (π x)

\frac{d}{d x} (arcsin (x - 1))

f (x) = - 5 t^{3} + 9 t + 7

What is area y=2sin(x),0<= x<= pi ?
The answer to area y=2sin(x),0<= x<= pi is 4