What is the derivative of (x^2-9)/(x-3) ?

The derivative of (x^2-9)/(x-3) is 1

What is the first derivative of (x^2-9)/(x-3) ?

The first derivative of (x^2-9)/(x-3) is 1

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derivative of

\frac{x ^{2} - 9}{x - 3}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 9}{x - 3})

Simplify

\frac{x ^{2} - 9}{x - 3} : x + 3

= \frac{d}{d x} (x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (3)

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 1 + 0

Simplify

= 1

\frac{( s + 7 )}{s ^{2} + 11 s + 30}

\frac{d}{d x} (\frac{x ^{n}}{n ^{2}})

\int_{- \infty}^{0} \frac{1}{3 - 2 x} d x

e^{- m x}

\frac{d ^{2}}{d x ^{2}} (11 tan (\frac{x}{10}))

What is the derivative of (x^2-9)/(x-3) ?
The derivative of (x^2-9)/(x-3) is 1
What is the first derivative of (x^2-9)/(x-3) ?
The first derivative of (x^2-9)/(x-3) is 1