What is the integral from-infinity to 0 of 1/(3-2x) ?

The integral from-infinity to 0 of 1/(3-2x) is diverges

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integral from-infinity to 0 of 1/(3-2x)

\int_{- \infty}^{0} \frac{1}{3 - 2 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{3 - 2 x} d x

Compute the indefinite integral:

\int \frac{1}{3 - 2 x} d x = - \frac{1}{2} ln ∣ 3 - 2 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{3 - 2 x} d x =

diverges

= diverges

e^{- m x}

\frac{d ^{2}}{d x ^{2}} (11 tan (\frac{x}{10}))

f (x) = 4 sin^{2} (0.5 x) + 1

\frac{d}{d x} (10000 (12 + x) e^{- 0.05 x})

x \to 1 lim (\frac{4 x - 1}{x - 1})

What is the integral from-infinity to 0 of 1/(3-2x) ?
The integral from-infinity to 0 of 1/(3-2x) is diverges