What is the limit as x approaches 1 of (4x-1)/(x-1) ?

The limit as x approaches 1 of (4x-1)/(x-1) is diverges

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limit as x approaches 1 of (4x-1)/(x-1)

x \to 1 lim (\frac{4 x - 1}{x - 1})

diverges

Solution steps

x \to 1 lim (\frac{4 x - 1}{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{4 x - 1}{x - 1}) = \infty

x \to 1 - lim (\frac{4 x - 1}{x - 1}) = - \infty

= diverges

\frac{1}{5} (9 x + 8)^{3}

f (x) = - 4 x^{2} - 5 x + 2

x \to 4 lim (\frac{x - 2}{x - 4})

\int_{0}^{π} x cos (3 x) d x

t^{2} y^{^{''}} + 9 t y^{^{'}} + 7 y = 0

What is the limit as x approaches 1 of (4x-1)/(x-1) ?
The limit as x approaches 1 of (4x-1)/(x-1) is diverges