What is the solution for y^{''}= x/(10),y(0)=0,y(0.015)=0 ?

The solution for y^{''}= x/(10),y(0)=0,y(0.015)=0 is y=(x^3)/(60)-(0.000003375x)/(0.9)

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y^{''}= x/(10),y(0)=0,y(0.015)=0

y^{^{''}} = \frac{x}{10}, y (0) = 0, y (0.015) = 0

y = \frac{x ^{3}}{60} - \frac{0.000003375 x}{0.9}

Solution steps

y^{''} (x) = \frac{x}{10}

Solve

y^{''} (x) = \frac{x}{10} : y^{'} (x) = \frac{x ^{2}}{20} + c_{1}

Solve

y^{'} (x) = \frac{x ^{2}}{20} + c_{1} : y = \frac{x ^{3}}{60} + c_{1} x + c_{2}

Apply initial conditions:

y = \frac{x ^{3}}{60} - \frac{0.000003375 x}{0.9}

y = \frac{x ^{3}}{60} - \frac{0.000003375 x}{0.9}

\frac{d}{d x} (x^{4} - x^{3} + x)

n = 0 \sum \infty \frac{n !}{4 ^{n}}

\int_{8}^{9} \frac{x}{x - 8} d x

\frac{\partial}{\partial x} (\frac{2 x}{1 + x + 2 y})

f (x) = ln (2 x + 1)

What is the solution for y^{''}= x/(10),y(0)=0,y(0.015)=0 ?
The solution for y^{''}= x/(10),y(0)=0,y(0.015)=0 is y=(x^3)/(60)-(0.000003375x)/(0.9)