What is (\partial)/(\partial x)(cos(3x+6y)) ?

The answer to (\partial)/(\partial x)(cos(3x+6y)) is -sin(3x+6y)*3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(cos(3x+6y))

\frac{\partial}{\partial x} (cos (3 x + 6 y))

- sin (3 x + 6 y) \cdot 3

Solution steps

\frac{\partial}{\partial x} (cos (3 x + 6 y))

Treat

y

as a constant

Apply the chain rule:

- sin (3 x + 6 y) \frac{\partial}{\partial x} (3 x + 6 y)

= - sin (3 x + 6 y) \frac{\partial}{\partial x} (3 x + 6 y)

\frac{\partial}{\partial x} (3 x + 6 y) = 3

= - sin (3 x + 6 y) \cdot 3

\frac{d y}{d x} + 0.8 x y = 4 x

\frac{\partial}{\partial x} (x \cdot i)

y \cdot \frac{d y}{d x} = 5 x (9 + y^{2})

x^{2} e^{x^{2}}

\int_{- 3}^{3} ∣ x + 2 ∣ d x

What is (\partial)/(\partial x)(cos(3x+6y)) ?
The answer to (\partial)/(\partial x)(cos(3x+6y)) is -sin(3x+6y)*3