What is the integral of cos(x)sin(x) ?

The integral of cos(x)sin(x) is (sin^2(x))/2+C

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integral of cos(x)sin(x)

\int cos (x) sin (x) d x

\frac{sin ^{2} ( x )}{2} + C

Solution steps

\int cos (x) sin (x) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (x)

= \frac{sin ^{2} ( x )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( x )}{2} + C

\int \frac{1}{2} e^{- \frac{x}{2}} d x

\frac{5}{1 + x ^{2}}

\frac{d y}{d x} = (\frac{( 2 y + 5 )}{8 x + 7})^{2}

\int 3 sin (x) cos (x) d x

\frac{\partial}{\partial x} (3 (\frac{( 4 + z )}{5 + x})^{2})

What is the integral of cos(x)sin(x) ?
The integral of cos(x)sin(x) is (sin^2(x))/2+C