What is the tangent of f(x)=(5x)/(x+3),\at x=2 ?

The tangent of f(x)=(5x)/(x+3),\at x=2 is y= 3/5 x+4/5

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tangent of f(x)=(5x)/(x+3),\at x=2

tangent of

f (x) = \frac{5 x}{x + 3}, at x = 2

y = \frac{3}{5} x + \frac{4}{5}

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = \frac{5 x}{x + 3} : \frac{df ( x )}{d x} = \frac{15}{( x + 3 ) ^{2}}

Compute the slope of

f (x) = \frac{5 x}{x + 3}

x = 2 : m = \frac{3}{5}

Find the line with slope m=

\frac{3}{5}

and passing through

(2, 2) : y = \frac{3}{5} x + \frac{4}{5}

y = \frac{3}{5} x + \frac{4}{5}

\frac{\partial}{\partial x} (ln (4 - t^{2}))

\int_{0}^{4} (10 - x) x d x

n = 0 \sum \infty \frac{2 ^{n}}{2 ^{n}}

e^{x} (x^{2} + 1) - 2 - x

y = 2^{x}

What is the tangent of f(x)=(5x)/(x+3),\at x=2 ?
The tangent of f(x)=(5x)/(x+3),\at x=2 is y= 3/5 x+4/5