What is the integral from 0 to 4 of (10-x)sqrt(x) ?

The integral from 0 to 4 of (10-x)sqrt(x) is 608/15

Popular >

integral from 0 to 4 of (10-x)sqrt(x)

\int_{0}^{4} (10 - x) x d x

\frac{608}{15}

Solution steps

\int_{0}^{4} (10 - x) x d x

Expand

(10 - x) x : 10 x - x^{\frac{3}{2}}

= \int_{0}^{4} 10 x - x^{\frac{3}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 10 x d x - \int_{0}^{4} x^{\frac{3}{2}} d x

\int_{0}^{4} 10 x d x = \frac{160}{3}

\int_{0}^{4} x^{\frac{3}{2}} d x = \frac{64}{5}

= \frac{160}{3} - \frac{64}{5}

Simplify

\frac{160}{3} - \frac{64}{5} : \frac{608}{15}

= \frac{608}{15}

n = 0 \sum \infty \frac{2 ^{n}}{2 ^{n}}

e^{x} (x^{2} + 1) - 2 - x

y = 2^{x}

\frac{\partial}{\partial z} (3 x z^{3} e^{y^{2}})

\frac{\partial}{\partial z} (x z + x yz)

What is the integral from 0 to 4 of (10-x)sqrt(x) ?
The integral from 0 to 4 of (10-x)sqrt(x) is 608/15