What is (\partial)/(\partial z)(xz+xyz) ?

The answer to (\partial)/(\partial z)(xz+xyz) is x+xy

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(\partial)/(\partial z)(xz+xyz)

\frac{\partial}{\partial z} (x z + x yz)

x + x y

Solution steps

\frac{\partial}{\partial z} (x z + x yz)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x z) + \frac{\partial}{\partial z} (x yz)

\frac{\partial}{\partial z} (x z) = x

\frac{\partial}{\partial z} (x yz) = x y

= x + x y

\int (x^{11} e^{x^{12}}) d x

\int \frac{3 x ^{2} + 2}{x ^{2}} d x

2 x + y^{2} = 8, x

\frac{\partial}{\partial y} (sin (y))

\frac{d}{d x} (ln (x + sin (x) + 1))

What is (\partial)/(\partial z)(xz+xyz) ?
The answer to (\partial)/(\partial z)(xz+xyz) is x+xy