What is the integral of (3x^2+2)/(x^2) ?

The integral of (3x^2+2)/(x^2) is -(3x^2+2)/x+6x+C

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integral of (3x^2+2)/(x^2)

\int \frac{3 x ^{2} + 2}{x ^{2}} d x

- \frac{3 x ^{2} + 2}{x} + 6 x + C

Solution steps

\int \frac{3 x ^{2} + 2}{x ^{2}} d x

Apply Integration By Parts

: - \frac{3 x ^{2} + 2}{x} - \int - 6 d x

= - \frac{3 x ^{2} + 2}{x} - \int - 6 d x

\int - 6 d x = - 6 x

= - \frac{3 x ^{2} + 2}{x} - (- 6 x)

Simplify

= - \frac{3 x ^{2} + 2}{x} + 6 x

Add a constant to the solution

= - \frac{3 x ^{2} + 2}{x} + 6 x + C

2 x + y^{2} = 8, x

\frac{\partial}{\partial y} (sin (y))

\frac{d}{d x} (ln (x + sin (x) + 1))

y = \frac{( x ^{2} + 1 ) ^{5}}{( 1 - x ^{2} ) ^{5}}

f (x) = \frac{ln ( x )}{2} + 2

What is the integral of (3x^2+2)/(x^2) ?
The integral of (3x^2+2)/(x^2) is -(3x^2+2)/x+6x+C