en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 1/(x-3),\at x=8

Solution

tangent of

f (x) = \frac{1}{x - 3}, at x = 8

Solution

y = - \frac{1}{25} x + \frac{13}{25}

Solution steps

Find the tangent point:

(8, \frac{1}{5})

Find the slope of

f (x) = \frac{1}{x - 3} : \frac{df ( x )}{d x} = - \frac{1}{( x - 3 ) ^{2}}

Compute the slope of

f (x) = \frac{1}{x - 3}

at

x = 8 : m = - \frac{1}{25}

Find the line with slope m=

- \frac{1}{25}

and passing through

(8, \frac{1}{5}) : y = - \frac{1}{25} x + \frac{13}{25}

y = - \frac{1}{25} x + \frac{13}{25}

Popular Examples

integral of t^2sin(t)

\int t^{2} sin (t) d t

derivative of f(t)=cos^2(pi/2-t)derivative of

f (t) = cos^{2} (\frac{π}{2} - t)

derivative of 2x^2-5x+2

\frac{d}{d x} (2 x^{2} - 5 x + 2)

(x+2)^2y^'+3(x+2)y=4

(x + 2)^{2} y^{^{'}} + 3 (x + 2) y = 4

limit as x approaches 0+of 1+xe^{(2/x)}

x \to 0 + lim (1 + x e^{(\frac{2}{x})})

Frequently Asked Questions (FAQ)

What is the tangent of f(x)= 1/(x-3),\at x=8 ?
The tangent of f(x)= 1/(x-3),\at x=8 is y=-1/25 x+13/25