What is the derivative of 2x^2-5x+2 ?

The derivative of 2x^2-5x+2 is 4x-5

What is the first derivative of 2x^2-5x+2 ?

The first derivative of 2x^2-5x+2 is 4x-5

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\frac{d}{d x} (2 x^{2} - 5 x + 2)

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (2) = 0

= 4 x - 5 + 0

Simplify

= 4 x - 5

(x + 2)^{2} y^{^{'}} + 3 (x + 2) y = 4

x \to 0 + lim (1 + x e^{(\frac{2}{x})})

\frac{d y}{d x} = 2 y + y^{5}, y (0) = 1

\int e^{6 t} d t

f (x) = \frac{A}{x ^{10}} + B e^{x}

What is the derivative of 2x^2-5x+2 ?
The derivative of 2x^2-5x+2 is 4x-5
What is the first derivative of 2x^2-5x+2 ?
The first derivative of 2x^2-5x+2 is 4x-5