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Popular >

derivative of f(x)= A/(x^{10)}+Be^x

Solution

derivative of

f (x) = \frac{A}{x ^{10}} + B e^{x}

Solution

- \frac{10 A}{x ^{11}} + B e^{x}

Solution steps

\frac{d}{d x} (\frac{A}{x ^{10}} + B e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{A}{x ^{10}}) + \frac{d}{d x} (B e^{x})

\frac{d}{d x} (\frac{A}{x ^{10}}) = - \frac{10 A}{x ^{11}}

\frac{d}{d x} (B e^{x}) = B e^{x}

= - \frac{10 A}{x ^{11}} + B e^{x}

Popular Examples

y^'-5y=6e^{5x},y(0)=0

y^{^{'}} - 5 y = 6 e^{5 x}, y (0) = 0

derivative of ln(2x^2-3x+1)

\frac{d}{d x} (ln (2 x^{2} - 3 x + 1))

derivative of y=x^2+5x+6 derivative of

y = x^{2} + 5 x + 6

tangent of f(x)=xsqrt(x),\at x=9 tangent of

f (x) = x x, at x = 9

integral of cos^{(5)}(5x)sin(5x)

\int cos^{(5)} (5 x) sin (5 x) d x

Frequently Asked Questions (FAQ)

What is the derivative of f(x)= A/(x^{10)}+Be^x ?
The derivative of f(x)= A/(x^{10)}+Be^x is -(10A)/(x^{11)}+Be^x
What is the first derivative of f(x)= A/(x^{10)}+Be^x ?
The first derivative of f(x)= A/(x^{10)}+Be^x is -(10A)/(x^{11)}+Be^x