What is the derivative of y= 6/(sqrt(x)) ?

The derivative of y= 6/(sqrt(x)) is -3/(x^{3/2)}

What is the first derivative of y= 6/(sqrt(x)) ?

The first derivative of y= 6/(sqrt(x)) is -3/(x^{3/2)}

derivative of

y = \frac{6}{x}

- \frac{3}{x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{6}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

6 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{3}{x ^{\frac{3}{2}}}

= - \frac{3}{x ^{\frac{3}{2}}}

\frac{d}{d x} (4 x x)

\int \frac{6}{6 x + 1} d x

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 8}{x})

\frac{d}{d y} (x^{2} - x y + 2)

y = \frac{5 + x f ( x )}{x}

What is the derivative of y= 6/(sqrt(x)) ?
The derivative of y= 6/(sqrt(x)) is -3/(x^{3/2)}
What is the first derivative of y= 6/(sqrt(x)) ?
The first derivative of y= 6/(sqrt(x)) is -3/(x^{3/2)}