What is the first d/(dy)(x^2-xy+2) ?

The first d/(dy)(x^2-xy+2) is -x

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d/(dy)(x^2-xy+2)

\frac{d}{d y} (x^{2} - x y + 2)

- x

Solution steps

\frac{d}{d y} (x^{2} - x y + 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (x^{2}) - \frac{d}{d y} (x y) + \frac{d}{d y} (2)

\frac{d}{d y} (x^{2}) = 0

\frac{d}{d y} (x y) = x

\frac{d}{d y} (2) = 0

= 0 - x + 0

Simplify

= - x

\frac{d}{d x} (10 x^{3} tan (x))

x \to 5 lim (x^{2} - 9)

\frac{d y}{d x} = 7 x 5 y + 3

\frac{d}{d x} (\frac{2000}{sin ( 3 x )})

y = \frac{5 + x f ( x )}{x}