What is the solution for (dy)/(dx)=(y^2x)/(x^2+1) ?

The solution for (dy)/(dx)=(y^2x)/(x^2+1) is y=-2/(ln(x^2+1)+c_{1)}

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(dy)/(dx)=(y^2x)/(x^2+1)

\frac{d y}{d x} = \frac{y ^{2} x}{x ^{2} + 1}

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

Solution steps

\frac{d y}{d x} = \frac{y ^{2} x}{x ^{2} + 1}

Solve separable ODE:

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

6 x - 2 x^{2} = y, (3, 4)

y^{^{''}} - 8 y^{^{'}} + 16 y = \frac{12 e ^{4 t}}{( t ^{2} + 1 )}

y = sin (x) cos (x), at x = \frac{3 π}{4}

θ \to \frac{π}{2} lim (3 sin (θ))

\frac{d}{d x} (3 x^{2} - 8)

What is the solution for (dy)/(dx)=(y^2x)/(x^2+1) ?
The solution for (dy)/(dx)=(y^2x)/(x^2+1) is y=-2/(ln(x^2+1)+c_{1)}