What is the tangent of f(x)=sqrt(2x),(18,6) ?

The tangent of f(x)=sqrt(2x),(18,6) is y= 1/6 x+3

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tangent of f(x)=sqrt(2x),(18,6)

tangent of

f (x) = 2 x, (18, 6)

y = \frac{1}{6} x + 3

Solution steps

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{2 x}

Compute the slope of

f (x) = 2 x

(18, 6) : m = \frac{1}{6}

Find the line with slope m=

\frac{1}{6}

and passing through

(18, 6) : y = \frac{1}{6} x + 3

y = \frac{1}{6} x + 3

\frac{d y}{d x} = \frac{e ^{y} + 1}{e ^{y}}

x = - 2, x = 1, y = 2 x^{2} + 7, y = 0

y^{^{'}} + 2 x y = 2 x e^{- x^{2}}

x \to 0 lim (\frac{x + 1}{x})

\int_{1}^{3} \frac{2}{x ^{3}} d x

What is the tangent of f(x)=sqrt(2x),(18,6) ?
The tangent of f(x)=sqrt(2x),(18,6) is y= 1/6 x+3