What is the limit as x approaches 0 of (sqrt(x+1))/x ?

The limit as x approaches 0 of (sqrt(x+1))/x is diverges

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limit as x approaches 0 of (sqrt(x+1))/x

x \to 0 lim (\frac{x + 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{x + 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x + 1}{x}) = \infty

x \to 0 - lim (\frac{x + 1}{x}) = - \infty

= diverges

\int_{1}^{3} \frac{2}{x ^{3}} d x

\int \frac{x ^{n - 1}}{a + b x ^{n}} d x

\int_{0}^{1} \frac{e ^{- x}}{x} d x

\frac{d y}{d x} = \frac{y ^{2} x}{x ^{2} + 1}

6 x - 2 x^{2} = y, (3, 4)

What is the limit as x approaches 0 of (sqrt(x+1))/x ?
The limit as x approaches 0 of (sqrt(x+1))/x is diverges