What is the tangent of y=sin(x)cos(x),\at x=(3pi)/4 ?

The tangent of y=sin(x)cos(x),\at x=(3pi)/4 is y=-1/2

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tangent of y=sin(x)cos(x),\at x=(3pi)/4

tangent of

y = sin (x) cos (x), at x = \frac{3 π}{4}

y = - \frac{1}{2}

Solution steps

Find the tangent point:

(\frac{3 π}{4}, - \frac{1}{2})

Find the slope of

y = sin (x) cos (x) : \frac{d y}{d x} = cos (2 x)

Compute the slope of

y = sin (x) cos (x)

x = \frac{3 π}{4} : m = 0

Find the line with slope m=

0

and passing through

(\frac{3 π}{4}, - \frac{1}{2}) : y = - \frac{1}{2}

y = - \frac{1}{2}

θ \to \frac{π}{2} lim (3 sin (θ))

\frac{d}{d x} (3 x^{2} - 8)

f (x) = ∣ x - 3 ∣

\frac{\partial}{\partial x} (\frac{8.31 x}{y})

f (x) = 2 x^{2} - 7 x + 5, at x = 2

What is the tangent of y=sin(x)cos(x),\at x=(3pi)/4 ?
The tangent of y=sin(x)cos(x),\at x=(3pi)/4 is y=-1/2