What is the first derivative of 3x^2-8 ?

The first derivative of 3x^2-8 is 6x

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derivative of 3x^2-8

\frac{d}{d x} (3 x^{2} - 8)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (8)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (8) = 0

= 6 x - 0

Simplify

= 6 x

f (x) = ∣ x - 3 ∣

\frac{\partial}{\partial x} (\frac{8.31 x}{y})

f (x) = 2 x^{2} - 7 x + 5, at x = 2

\frac{d}{d x} (9 ln (1 + x^{2}))

x \to 6 lim (c x^{2} + 7 x)