What is the limit as x approaches+(-1) of x^2+x+1 ?

The limit as x approaches+(-1) of x^2+x+1 is 1

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limit as x approaches+(-1) of x^2+x+1

x \to + (- 1) lim (x^{2} + x + 1)

1

Solution steps

x \to - 1 lim (x^{2} + x + 1)

Plug in the value

x = - 1

= (- 1)^{2} - 1 + 1

Simplify

(- 1)^{2} - 1 + 1 : 1

= 1

(t^{2} + x^{2}) d t + (2 t x - x) d x = 0

\frac{d}{d x} (x^{4} - 4 x^{2} - 10 x)

x \to 0 - lim (- 7 x^{2} + 5 x)

y = \frac{6 x - 1}{8 x + 3}

tan^{- 1} (x)

What is the limit as x approaches+(-1) of x^2+x+1 ?
The limit as x approaches+(-1) of x^2+x+1 is 1