What is the derivative of y=(6x-1)/(8x+3) ?

The derivative of y=(6x-1)/(8x+3) is (26)/((8x+3)^2)

What is the first derivative of y=(6x-1)/(8x+3) ?

The first derivative of y=(6x-1)/(8x+3) is (26)/((8x+3)^2)

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derivative of

y = \frac{6 x - 1}{8 x + 3}

\frac{26}{( 8 x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6 x - 1}{8 x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 6 x - 1 ) ( 8 x + 3 ) - \frac{d}{d x} ( 8 x + 3 ) ( 6 x - 1 )}{( 8 x + 3 ) ^{2}}

\frac{d}{d x} (6 x - 1) = 6

\frac{d}{d x} (8 x + 3) = 8

= \frac{6 ( 8 x + 3 ) - 8 ( 6 x - 1 )}{( 8 x + 3 ) ^{2}}

Expand

6 (8 x + 3) - 8 (6 x - 1) : 26

= \frac{26}{( 8 x + 3 ) ^{2}}

tan^{- 1} (x)

y^{^{'}} = 6 y + 2 t - 4

\frac{d}{d x} ((2 - 6 x)^{0.5})

\frac{d}{d x} (0.1 x^{2})

\int \frac{x + 2}{4 - x ^{2}} d x

What is the derivative of y=(6x-1)/(8x+3) ?
The derivative of y=(6x-1)/(8x+3) is (26)/((8x+3)^2)
What is the first derivative of y=(6x-1)/(8x+3) ?
The first derivative of y=(6x-1)/(8x+3) is (26)/((8x+3)^2)