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Popular >

y^'=6y+2t-4

Solution

y^{^{'}} = 6 y + 2 t - 4

Solution

y = - \frac{t}{3} + \frac{11}{18} + c_{1} e^{6 t}

Solution steps

y^{'} (t) = 6 y + 2 t - 4

Solve linear ODE:

y = - \frac{t}{3} + \frac{11}{18} + c_{1} e^{6 t}

y = - \frac{t}{3} + \frac{11}{18} + c_{1} e^{6 t}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=6y+2t-4 ?
The solution for y^'=6y+2t-4 is y=-t/3+11/18+c_{1}e^{6t}