What is (\partial)/(\partial x)(x^3+yz^2) ?

The answer to (\partial)/(\partial x)(x^3+yz^2) is 3x^2

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(\partial)/(\partial x)(x^3+yz^2)

\frac{\partial}{\partial x} (x^{3} + y z^{2})

3 x^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} + y z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) + \frac{\partial}{\partial x} (y z^{2})

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (y z^{2}) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

x \to 3 lim (\frac{1}{ln ^{2} ( \frac{x}{3} )})

(x^{2} - 2)^{2}

\frac{\partial}{\partial z} (x y + yz)

\int e^{3 x} (e^{3 x - 8})^{5} d x

y^{^{'}} = 3 x + y

What is (\partial)/(\partial x)(x^3+yz^2) ?
The answer to (\partial)/(\partial x)(x^3+yz^2) is 3x^2