What is the derivative of 6log_{9}(x) ?

The derivative of 6log_{9}(x) is 3/(ln(3)x)

What is the first derivative of 6log_{9}(x) ?

The first derivative of 6log_{9}(x) is 3/(ln(3)x)

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derivative of

6 lo g_{9} (x)

\frac{3}{ln ( 3 ) x}

Solution steps

\frac{d}{d x} (6 lo g_{9} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (lo g_{9} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= 6 \cdot \frac{1}{x ln ( 9 )}

Simplify

6 \cdot \frac{1}{x ln ( 9 )} : \frac{3}{ln ( 3 ) x}

= \frac{3}{ln ( 3 ) x}

5 cos (9 x), 5 - 5 cos (9 x), [0, \frac{π}{9}]

f (x) = (x - 3) (x^{2} - 6 x + 6)

e^{- s} \frac{1}{s}

4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x

\int_{0}^{100} e^{- \frac{x}{0.033}} d x

What is the derivative of 6log_{9}(x) ?
The derivative of 6log_{9}(x) is 3/(ln(3)x)
What is the first derivative of 6log_{9}(x) ?
The first derivative of 6log_{9}(x) is 3/(ln(3)x)