What is the integral of 3sin^2(t)cos(t) ?

The integral of 3sin^2(t)cos(t) is sin^3(t)+C

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integral of 3sin^2(t)cos(t)

\int 3 sin^{2} (t) cos (t) d t

sin^{3} (t) + C

Solution steps

\int 3 sin^{2} (t) cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int sin^{2} (t) cos (t) d t

Apply u-substitution

: \int u^{2} d u

= 3 \cdot \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= 3 \cdot \frac{u ^{3}}{3}

Substitute back

u = sin (t)

= 3 \cdot \frac{sin ^{3} ( t )}{3}

Simplify

3 \cdot \frac{sin ^{3} ( t )}{3} : sin^{3} (t)

= sin^{3} (t)

Add a constant to the solution

= sin^{3} (t) + C

\int x^{4} e^{3 x} d x

\frac{d}{d x} (2 sec (2 x) tan (2 x))

0.125 x 64 - x^{2}

\frac{\partial}{\partial x} (x^{2} + sin (x y))

\frac{d}{d x} (a cos (b x))

What is the integral of 3sin^2(t)cos(t) ?
The integral of 3sin^2(t)cos(t) is sin^3(t)+C