What is the limit as x approaches-4 of 1/(x^2-16) ?

The limit as x approaches-4 of 1/(x^2-16) is diverges

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limit as x approaches-4 of 1/(x^2-16)

x \to - 4 lim (\frac{1}{x ^{2} - 16})

diverges

Solution steps

x \to - 4 lim (\frac{1}{x ^{2} - 16})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 4 + lim (\frac{1}{x ^{2} - 16}) = - \infty

x \to - 4 - lim (\frac{1}{x ^{2} - 16}) = \infty

= diverges

(1 + x^{4}) \frac{d y}{d x} = 2 x^{3} (1 - y^{2})

n = 0 \sum \infty \frac{1}{2 ^{2 n - 1}}

\int_{0}^{a} \frac{1}{( a + r - x ) ^{2}} d x

x, x^{3}

\int \frac{sin ( x )}{cos ^{6} ( x )} d x

What is the limit as x approaches-4 of 1/(x^2-16) ?
The limit as x approaches-4 of 1/(x^2-16) is diverges