What is the derivative of x^4+3x ?

The derivative of x^4+3x is 4x^3+3

What is the first derivative of x^4+3x ?

The first derivative of x^4+3x is 4x^3+3

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\frac{d}{d x} (x^{4} + 3 x)

4 x^{3} + 3

Solution steps

\frac{d}{d x} (x^{4} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x) = 3

= 4 x^{3} + 3

\int \frac{lo g _{3} ( x )}{x} d x

y^{^{'}} + (\frac{1 + x}{x}) y = 0

y = ln (x^{2}), (5, ln (25))

f (x) = 3 x^{8}

What is the derivative of x^4+3x ?
The derivative of x^4+3x is 4x^3+3
What is the first derivative of x^4+3x ?
The first derivative of x^4+3x is 4x^3+3