What is the integral of-36cos(x) ?

The integral of-36cos(x) is -36sin(x)+C

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integral of-36cos(x)

\int - 36 cos (x) d x

- 36 sin (x) + C

Solution steps

\int - 36 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 36 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - 36 sin (x)

Add a constant to the solution

= - 36 sin (x) + C

\int 1 + y d y

x \to 0 lim (\frac{3 x ^{2}}{x})

y = (x^{3} - 3 x) (2 x^{2} + 3 x + 5)

x \to 0 + lim (x (ln (x^{2})))

\frac{d}{d x} (\frac{3 sin ( x ) - 2 cos ( x )}{5})