What is the sum from n=1 to infinity of (n!)/(20^n) ?

The sum from n=1 to infinity of (n!)/(20^n) is diverges

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sum from n=1 to infinity of (n!)/(20^n)

n = 1 \sum \infty \frac{n !}{2 0 ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{n !}{2 0 ^{n}}

Apply Series Ratio Test:

diverges

= diverges

\int (2 t - 1) d t

\int (2 - x^{2}) d x

y y^{^{'}} - e^{x} = 0

y = 3 - x^{3} (0.3)

x \to \infty lim (1)

What is the sum from n=1 to infinity of (n!)/(20^n) ?
The sum from n=1 to infinity of (n!)/(20^n) is diverges