What is the derivative of f(x)=x^2-8x ?

The derivative of f(x)=x^2-8x is 2x-8

What is the first derivative of f(x)=x^2-8x ?

The first derivative of f(x)=x^2-8x is 2x-8

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derivative of

f (x) = x^{2} - 8 x

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

= 2 x - 8

\frac{\partial}{\partial x} ((e^{x} - 2 y^{- 3})^{\frac{2}{5}})

\frac{\partial}{\partial x} (3 (\frac{y}{x})^{\frac{1}{2}})

f^{^{''}} (x) = 4 x

\int_{0}^{3} π (6 3 y)^{2} d y

(x^{2} + y^{2}) d x - x y d y = 0

What is the derivative of f(x)=x^2-8x ?
The derivative of f(x)=x^2-8x is 2x-8
What is the first derivative of f(x)=x^2-8x ?
The first derivative of f(x)=x^2-8x is 2x-8